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(A) The area of a circle is given by $A = \pi r^2$. Given that the radius $r$ increases from $r_1 = 3 \, cm$ to $r_2 = 3.2 \, cm$. The change in radiu

Vedclass · Accepted Answer

$1.24\pi \, cm^2$

Vedclass · Answer

(A) The area of a circle is given by $A = \pi r^2$. Given that the radius $r$ increases from $r_1 = 3 \, cm$ to $r_2 = 3.2 \, cm$. The change in radius is $\Delta r = 3.2 - 3 = 0.2 \, cm$. The increase in the area of the circle is $\Delta A = A(r_2) - A(r_1) = \pi(r_2^2 - r_1^2)$. Substituting the values,we get $\Delta A = \pi((3.2)^2 - (3)^2)$. $\Delta A = \pi(10.24 - 9) = 1.24\pi \, cm^2$. Therefore,the correct option is $A$.

If the radius of a circle increases from $3 \, cm$ to $3.2 \, cm$,then the increase in the area of the circle is

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